After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear speed of v = 3. 22 m/s (Figure 10-24). To reach the rack, the ball rolls up a ramp that gives the ball a h = 0. 50 m vertical rise. What is the speed of the ball when it reaches the top of the ramp?
m/s
After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear..?
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this will be solved using energy conservation.
The energy of the rolling ball has two components:
translational
.5*m*v^2
and rotational
.5*I*ω^2
where ω is the angular speed and ω=v/r
I is the moment of inertia.
Assuming the bowling ball to be a solid sphere
I=2*m*r^2/5
the gain in PE is m*g*h
setting up the equations, note the m will divide out
3.22^2*(.5+1/5)-9.81*0.5=v^2*(.5+1/5)
solve for v
v=1.83 m/s
j