the one that is being graphed is the speed of the bowling ball (distance VS time). . . there were 6 lines, labeled from 0m to 25m, each was 5 spaced distances. . . there were students that were assined in each line,,, as the bowling ball passes each line, student will record the time in seconds. . . everyone would start their stopwatches at the same time. . .
How can we use the bowling ball lab to help us understand distance vs. time graphs?
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Don’t have a clue what you are asking. But I do know this…distance vs. time is a very useful graph.
Say you have the following data for a bowling ball rolled down an alley that is 30 m long:
Distance (meter)……..Time (sec)
0=================0
10================2
20================4
30================6
Graph these pairs of data as four data points [(0,0), (2,10), (4,20), and (6,30)] on an S vs T graph (distance vs time), with S as the Y axis and T as the X. [NOTE: By convention, the X data point is given first; so in general (X,Y) = (T,S) is used.]
Now answer this from the graph. What’s the average velocity of the bowling ball down the alley? By definition velocity v = dS/dt = (S1 – S0)/(T1 – T0); where S1 and S0 are distances traveled at times T1 and T0 respectively.
So the average velocity over the 30 meter alley is v = (S1 – S0)/(T1 – T0) = (30 – 0)/(6 – 0) = 30/6 = 5 mps. So the bowling ball, as gathered from the S vs. T graph, traveled an average of 5 m/sec during the 30 meter run.
And that’s one way to use a distance vs. time graph.
shahzaib asad